The relation R is defined in the set {1, 2, 3, 4, 5, 6} as R = {(a, b): b = a + 1}, then
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R is neither reflexive nor symmetric nor transitive
Let, A = {l, 2, 3, 4, 5, 6}
The relation R is defined on set A is
R = {(a, b): b = a + 1}. Therefore, R = {(1, 2), (2, 3), (3, 4), (4, 5), (5, 6)}
Now, 6
A but (6, 6)
R.
Therefore, R is not reflexive.
It can be observed that (1, 2)
R but (2,1)
R. Therefore, R is not symmetric.
Now, (1, 2), (2, 3)
R but (l, 3)
R Therefore, R is not transitive.
Hence, R is neither reflexive nor symmetric nor transitive
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